Search: id:A064387 Results 1-1 of 1 results found. %I A064387 %S A064387 1,3,6,2,7,13,20,12,21,11,22,10,23,9,24,8,25,43,62,42,63,41,18, %T A064387 44,19,45,72,100,71,101,70,38,5,39,4,40,77,115,76,36,78,120,163, %U A064387 119,74,28,75,27,79,29,80,132,185,131,186,130,73,15,81,141,202 %N A064387 Variation (2) on Recaman's sequence (A005132): to get a(n), we first try to subtract n from a(n-1): a(n) = a(n-1)-n if positive and not already in the sequence; if not then a(n) = a(n-1)+n+i, where i > = 0 is the smallest number such that a(n-1)+n+i has not already appeared. %C A064387 Variation (4) (A064389) is the nicest of these variations. %C A064387 I would also like to get the following sequences: number of steps before n appears (or 0 if n never appears), list of numbers that never appear, height of n (cf. A064288, A064289, A064290), etc. %D A064387 Suggested by J. C. Lagarias. %H A064387 Index entries for sequences related to Recaman's sequence %H A064387 Nick Hobson, Python program for this sequence %p A064387 h := array(1..100000); maxt := 100000; a := array(1..1000); a[1] := 1; h[1] := 1; for nx from 2 to 1000 do t1 := a[nx-1]-nx; if t1>0 and h[t1] <> 1 then a[nx] := t1; if t1 < maxt then h[t1] := 1; fi; else for i from 0 to 1000 do t1 := a[nx-1]+nx+i; if h[t1] <> 1 then a[nx] := t1; if t1 < maxt then h[t1] := 1; fi; break; fi; od; fi; od; evalm(a); %Y A064387 Cf. A005132, A046901, A064388, A064389. Agrees with A064389 for first 187 terms, then diverges. %Y A064387 Sequence in context: A076543 A005132 A064388 this_sequence A064389 A118201 A113880 %Y A064387 Adjacent sequences: A064384 A064385 A064386 this_sequence A064388 A064389 A064390 %K A064387 nonn,easy %O A064387 1,2 %A A064387 N. J. A. Sloane (njas(AT)research.att.com), Sep 28 2001 Search completed in 0.001 seconds